[UVa]10340:All in All

利用兩個變數i,j，
i從t開始搜，
搜到與s[j]一樣就讓j++，
這樣到最後如果j與s字串的長度一樣，
即表示答案是Yes，
反之則是No。

[C](0.012)

	#include<stdio.h>
	#include<string.h>
	int main()
	{
	char s[100000] = {0}, t[100000] = {0};
	while( scanf( "%s%s", s, t ) != EOF )
	{
	int slength = strlen(s);
	int tlength = strlen(t);
	int i, j;
	for( i = 0, j = 0 ; i < tlength && j < slength ; i++ )
	if( t[i] == s[j] )
	j++;
	if( j == slength )
	printf( "Yes\n" );
	else
	printf( "No\n" );
	}
	return 0;
	}

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