[Zerojudge]a032: 階乘運算

利用迴圈即可得解。

[C++](4ms, 696KB)

	#include<iostream>
	using namespace std;
	int main()
	{
	long long n;
	while( cin >> n )
	{
	long long nf = 1;
	for( long long i = 2 ; i <= n ; i++ )
	nf *= i;
	cout << nf << endl;
	}
	return 0;
	}

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