[Zerojudge]a022: 迴文

利用字串處理，並且利用for來反轉字串，很快速即可過關。

[C++](0ms, 730KB)

	#include<iostream>
	using namespace std;
	int main()
	{
	string str;
	while( getline( cin, str ) )
	{
	string rev;
	for( int i = str.length()-1 ; i >= 0 ; i-- )
	rev += str[i];
	if( rev == str )
	cout << "yes\n";
	else
	cout << "no\n";
	}
	return 0;
	}

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