[Zerojudge]c022: 10783 - Odd Sum

照著題目所要求的奇數之和即可。

[C++](4ms, 708KB)

	#include<iostream>
	using namespace std;
	int main()
	{
	int T;
	while( cin >> T )
	{
	for( int i = 1 ; i <= T ; i++ )
	{
	int a, b;
	cin >> a >> b;
	int sum = 0;
	for( int j = a ; j <= b ; j++ )
	if( j % 2 )
	sum += j;
	cout << "Case " << i << ": " << sum << endl;
	}
	}
	return 0;
	}

view raw Zerojudgec022.cpp hosted with ❤ by GitHub