[Zerojudge]a006: 一元二次方程式

公式解，即可得。

P.S. 公式：(-b+sqrt(b*b-4*a*c))/(2*a) 以及 (-b-sqrt(b*b-4*a*c))/(2*a)

[C++](5ms, 704KB)

	#include<iostream>
	#include<cmath>
	using namespace std;
	int main()
	{
	int a, b, c;
	while( cin >> a >> b >> c )
	{
	if( b*b - 4*a*c < 0 )
	cout << "No real root\n";
	else if( b*b - 4*a*c == 0 )
	cout << "Two same roots x=" << -b/(2*a) << endl;
	else
	cout << "Two different roots x1=" << (-b + sqrt(b*b-4*a*c)) / (2*a) << " , x2=" << (-b - sqrt(b*b-4*a*c)) / (2*a) << endl;
	}
	return 0;
	}

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